MTH101 ASSignment 1 Solution 2021

MTH101 ASSignment 1 solution 2021

GET MTH101 ASSIGNMENT 1 SPRING 2021 SOLUTION FILE FROM THIS LINK 

MTH101 ASSignment 2 solution 2021

ASLAM U ALAIKUM DEAR STUDNETS DOWNLOAD COMPLETE SOLUTION FILES FROM THE LINK, WHICH IS AVAILABLE AT THE END OF THE PAGE. WORD SOLUTION FILE IS AVAILABLE AT THE END OF THE PAGE. SCROLL DOWN THE PAGE TO DOWNLOAD THE SOLUTION FILE.     SEE ALSO:   (Mth101 assignment solution 2)   Question: 1 Check the validity of Rolle’s Theorem for   on the interval [2, 10]. Solution: Part (a) f(x) = 1+(x-2)1/3___(equation  1) Put x=2 in equation (1) f(2) = 1+(2-2)1/3 f(2) = 1+(0)1/3 f(2) = 1 and f(x) = 1+(x-2)1/3___(equation  2) Put x=10 in equation (2) f(10) =1+(10-2)1/3 f(10) = 1+(10-2)1/3 f(10) = 1+(23)1/3 f(10) = 1+(2)1 f(10) = 1+2 f(10) = 3 As f(2) f(10), thus the given function is not continuous.   mth101 assignment 2 solution fall 2020 mth101 assignment 2 solution 2020  

MTH101 ASSignment 2 solution 2021

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